|
("Rich S." wrote)
>> In your illustration, the gunner fires straight back
>> before the Me-109 is directly behind the B17. He can hit
>> if he fires at precisely the moment his gun crosses the
>> flight path of the Me-109.
> Not so. The bullet simply falls to Earth and the ME-109 passes safely 50
> yards (or so) behind the B-17.
Agreed.
(For those who do not agree)
Think of a pickup truck driving along at 40 mph. I am standing in the bed
with a baseball.
When we reach the manhole cover in the middle of the street I let fly out
the back of the truck with my best stuff, which just happens to be a 40 mph
fastball <g>. That ball will not go past the manhole cover.
If you're a batter (or an ME-109) standing at the manhole cover - which
every kid knows is home plate - you won't get hit by my fastball ...or be
able to hit it. (I am unhittable!!)
Now, if I flip the ball into the air, but a little to the left, and you are
standing in the street when the truck drives by, you will be hit by a 40 mph
ball. Just thought I would toss that one out there :-)
So long as the ME-109 isn't moving (at all) in the same direction as the
"magic" B-17, when it crosses behind the Flying Fortress, it will be safe
from the bullet.. I'd think wind drift would not be an issue (with
perpendicular plane paths) since it will drift the B-17 too ... away from
the ME-109.
Montblack ..."car"
|
|
Re: Physics question
